(30/(x^2-9))-(5/(x-3))=(8/(x+3))

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Solution for (30/(x^2-9))-(5/(x-3))=(8/(x+3)) equation:


D( x )

x-3 = 0

x+3 = 0

x^2-9 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

30/(x^2-9)-(5/(x-3)) = 8/(x+3) // - 8/(x+3)

30/(x^2-9)-(5/(x-3))-(8/(x+3)) = 0

30/(x^2-9)-5*(x-3)^-1-8*(x+3)^-1 = 0

30/(x^2-9)-5/(x-3)-8/(x+3) = 0

(30*(x-3)*(x+3))/((x^2-9)*(x-3)*(x+3))+(-5*(x^2-9)*(x+3))/((x^2-9)*(x-3)*(x+3))+(-8*(x^2-9)*(x-3))/((x^2-9)*(x-3)*(x+3)) = 0

30*(x-3)*(x+3)-5*(x^2-9)*(x+3)-8*(x^2-9)*(x-3) = 0

15*x^2-5*x^3-8*x^3+24*x^2+45*x+72*x-216-135 = 0

39*x^2-13*x^3+117*x-351 = 0

39*x^2-13*x^3+117*x-351 = 0

13*(3*x^2-x^3+9*x-27) = 0

3*x^2-x^3+9*x-27 = 0

{ 1, -1, 3, -3, 9, -9, 27, -27 }

1

x = 1

3*x^2-x^3+9*x-27 = -16

1

-1

x = -1

3*x^2-x^3+9*x-27 = -32

-1

3

x = 3

3*x^2-x^3+9*x-27 = 0

3

x-3

9-x^2

3*x^2-x^3+9*x-27

x-3

x^3-3*x^2

9*x-27

27-9*x

0

9-x^2 = 0

DELTA = 0^2-(-1*4*9)

DELTA = 36

DELTA > 0

x = (36^(1/2)+0)/(-1*2) or x = (0-36^(1/2))/(-1*2)

x = -3 or x = 3

x in { -3, 3, 3}

13*(x+3)*(x-3)^2 = 0

(13*(x+3)*(x-3)^2)/((x^2-9)*(x-3)*(x+3)) = 0

(13*(x+3)*(x-3)^2)/((x^2-9)*(x-3)*(x+3)) = 0 // * (x^2-9)*(x-3)*(x+3)

13*(x+3)*(x-3)^2 = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -3}

x in { 3}

x belongs to the empty set

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